Physics - Rotation Question with Solution | TestHub

The moment of inertia of a uniform solid cylinder about its own axis is $I=\frac{1}{2}M{R}^2$. The rotational kinetic energy is given by $K_{rot}=\frac{1}{2}I{\omega }^2$. Substituting the value of $I$, we get $K_{rot}=\frac{1}{2}\left(\frac{1}{2}M{R}^2\right){\omega }^2=\frac{1}{4}M{R}^2{\omega }^2$.