In the circuit shown, S 1 is kept closed for long time. Then at t = 0 , Switch is thrown to S 2 position so that S 1 is open and S 2 closed. Then at t = In 2 , what is value of current in the

Question

In the circuit shown, S 1 ​ is kept closed for long time. Then at t = 0 , Switch is thrown to S 2 ​ position so that S 1 ​ is open and S 2 ​ closed. Then at t = In 2 , what is value of current in the inductor in ampere?

TestHub · Accepted Answer

t = 0 current through inductor = 4 a Time constant from lower loop is R L ​ = 2 2 ​ = 1 So current as a function of time in the loop is given by I = 4 e − t + 2 10 ​ [ 1 − e − t ] I = ( 4 − 5 ) e − t + 5 I = 5 − e t 1 ​ Put t = 1 n 2 I = 5 − 2 1 ​ = 4.5 A

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