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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACParallel AC circuitsMedium3 minQB

PhysicsMediummultiple choice

Passage / Comprehension

The circuit consists of a capacitor connected in parallel to a resistor $R$ with a coil of inductance $L$ in series with them. The power source could be an AC or a constant voltage DC source. When the AC source is applied then $X_{L} = X_{C} = R$ .

If an AC source $ξ = ξ_{0} cos ω t$ is applied across the input terminal, then:

Options:(select one or more)

Answer:

A, C

Solution:

$\hat{Z} = j X_{L} + \frac{R ( - j X _{C} )}{R - j X _{C}} = \frac{R}{2} (1 + j)$
Since:
$X_{L} = X_{C} = R$
$∣ Z ∣ = \frac{R}{2}$
$I_{0} = \frac{ξ _{0}}{R / 2} = \frac{2 ξ _{0}}{R}$ (A true, B false)
The peak current through the capacitor branch:
$\frac{ξ _{0}}{R}$ (C true, D false)
Printed key: A,C.

Subject:PhysicsTopic:EMI/ACSubtopic:Parallel AC circuits

⏱ 3mℹ️ Source: QB

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