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PhysicsRotationRotational KinematicsHard2 minPYQ_2023
PhysicsHardnumerical

A circular plate is rotating in horizontal plane, about an axis passing through its centre and perpendicular to the plate, with an angular velocityω. A person sits at the centre having two dumbbells in his hands. When he stretched out his hands, the moment of inertia of the system becomes triple. IfEbe the initial Kinetic energy of the system, then final Kinetic energy will beEx. The value ofxis

Answer:
3.00
Solution:

The kinetic energy is given by 

E=12Iω2=L22I

It is given that the new moment of inertia

 I'=3I 

Clearly, the final kinetic energy is

Ef=L22I'=L26IEf=E3

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics
2mℹ️ Source: PYQ_2023

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