A disc of mass 'm' and radius 'R' has a particle of mass 'm' attached to its surface at distance R/2 from centre. The disc is placed on rough surface with point P on its

Question

A disc of mass 'm' and radius 'R' has a particle of mass 'm' attached to its surface at distance R/2 from centre. The disc is placed on rough surface with point P on its periphery as point of contact. If there is no slipping and if the system is at rest at the instant shown,

TestHub · Accepted Answer

I P ​ = 2 3 m R 2 ​ + 4 5 m R 2 ​ = 4 11 m R 2 ​ ; α = I P ​ τ P ​ ​ = 4 11 m R 2 ​ 2 m g 4 R ​ ​ = 11 R 2 g ​ (B) a C ​ = R α = 11 2 g ​ CORRECT (C) ( a COM ​ ) x ​ = R α = 11 2 g ​ ⇒ f = 2 m ( a COM ​ ) x ​ = 11 4 m g ​ CORRECT (A) a COM ​ = 4 R 17 ​ ​ α = 22 17 ​ g ​  = 41 8 g ​ INCORRECT (D) ( a COM ​ ) y ​ = 4 R ​ α = 22 g ​ ⇒ N = 2 m g − 22 2 m g ​ = 11 21 m g ​ ; tan θ = N f ​ = 21 4 ​  = 39 8 ​ INCORRECT

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