Physics - Rotation Question with Solution | TestHub

moment of inertia of a disc about an axis passing through its centre and normal to its plane

$I=\frac{1}{2}m{R}^2$

The disc is now folded along a diameter such that the two halves are mutually perpendicular

In this moment of inertia about this diameter$I=I_{\mathrm{d}}+I_{\mathrm{d}}$

$I=2I_{\mathrm{d}}$

$I_{\mathrm{d}}=\frac{1}{2}I$

For a diameter;$I_{\mathrm{d}}=\frac{I}{2}$