a string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m . If the string is now pulled with a horizontal force of 40 N , and the cylinder is rolling without slipping on a horizontal su

Question

a string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m . If the string is now pulled with a horizontal force of 40 N , and the cylinder is rolling without slipping on a horizontal surface (see figure), then the angular acceleration of the cylinder will be (Neglect the mass and thickness of the string)

TestHub · Accepted Answer

From newton's second law 40 + f = m ( R α ) ...(i) Taking torque about 0 we get 40 × R − f × R = I α 40 × R − f × R = mR 2 α 40 − f = mR α ...(ii) Solving equation (i) and (ii) α = mR 40 ​ = 16 rad / s 2

Physics - Rotation Question with Solution | TestHub

Options:

Doubts & Discussion