Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A ring starts to roll down the inclined plane of height $h$ without slipping. The velocity when it reaches the ground is

Answer:

Solution:

$mgh = \frac{1}{2} m v^{2} + \frac{1}{2} {Iω}^{2}$

$= \frac{1}{2} m v^{2} + \frac{1}{2} m r^{2} \frac{v^{2}}{r^{2}}$

$gh = v^{2}$

$v = \sqrt{gh}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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