Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsMedium2 minPYQ_2024

PhysicsMediumnumerical

A hollow sphere is rolling on a plane surface about its axis of symmetry. The ratio of rotational kinetic energy to its total kinetic energy is $\frac{x}{5}$ . The value of $x$ is _____ .

Answer:

2.00

Solution:

$\frac{\frac{1}{2} I ω ^{2}}{\frac{1}{2} I ω ^{2} + \frac{1}{2} mv ^{2}} = \frac{( \frac{1}{2} ) ( \frac{2}{3} mR ^{2} ) ω ^{2}}{( \frac{1}{2} ) ( \frac{2}{3} mR ^{2} ) ω ^{2} + \frac{1}{2} m ( R ω ) ^{2}} = \frac{\frac{2}{3}}{\frac{2}{3} + 1} = \frac{2}{5} x = 2$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2024

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