Start Free Mock LoginAlready registered? Login here

Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsMedium2 minPYQ_2006

PhysicsMediumsingle choice

A uniform rod of length $l$ and mass $m$ is free to rotate in a vertical plane about $A$ . The rod initially in horizontal position is released. The initial angular acceleration of the rod is (moment of inertia of the rod about $A$ is $\frac{m l ^{2}}{3}$ ).
NEET 2006

Options:

Answer:

Solution:

Here torque
$τ = m g (\frac{1}{2})$ M. I. of $rod$ about $A$ is: $I = \frac{m l ^{2}}{3}$ $∴$ Angular acceleration of the rod is $α = \frac{τ}{I}$ $α = \frac{m g ( \frac{1}{2} )}{\frac{m l ^{2}}{3}} = \frac{3 g}{2 l} .$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2006

Doubts & Discussion

Loading discussions...