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PhysicsRotationRotational KinematicsMedium2 minPYQ_2023
PhysicsMediumnumerical

A thin uniform rod of length2 m, cross sectional areaAand densitydis rotated about an axis passing through the centre and perpendicular to its length with angular velocityω. If value ofωin terms of its rotational kinetic energyEisαEAd, then the value ofαis ______.

Answer:
3.00
Solution:

Rotational kinetic energy is given by E=12Iω2, here, I is moment of inertia of rod about an axis through its centre and perpendicular to it.

So, E=12ml212ω2

E=12dAl312ω2    mass=density×volume

E=dA(2)324ω2

ω=3EdA

Thus, the value of α=3.

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics
2mℹ️ Source: PYQ_2023

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