A string is wrapped around the rim of a wheel of moment of inertia 0.40 kgm 2 and radius 10 cm . The wheel is free to rotate about its axis. Initially the wheel is at rest. The string is now pulled by

Question

A string is wrapped around the rim of a wheel of moment of inertia $0.40 kgm^{2}$ and radius $10 cm$ . The wheel is free to rotate about its axis. Initially the wheel is at rest. The string is now pulled by a force of $40 N$ . The angular velocity of the wheel after $10 s$ is $x rad / s$ , where $x$ is _______

Answer:

100.00

Solution:

$τ = FR = I α \Rightarrow 40 \times 0.1 = 0.4 α α = 10 rad / s^{2} W_{f} = 10 \times 10 = 100 rad / s$

TestHub · Accepted Answer

​ τ = FR = I α ⇒ 40 × 0.1 = 0.4 α α = 10 rad / s 2 W f ​ = 10 × 10 = 100 rad / s ​

Physics - Rotation Question with Solution | TestHub

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