Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsProjectile motionMedium2 minQB

PhysicsMediummultiple choice

Two particles are thrown from same point in same vertical plane as shown in figure simultaneously. Then indicate the correct statement(s).

Answer:

B, C, D

Solution:

From the figure, both particles reach the same maximum height.

$H = \frac{u _{y}^{2}}{2 g} same \Rightarrow u_{y A} = u_{y B}$ ; vertical motion of both is identical throughout the flight. (D) is correct

$T = \frac{2 u _{y}}{g}$ is the same for both, so (A) is wrong.

B has the greater range with the same time of flight: $R = u_{x} T \Rightarrow u_{x B} > u_{x A}$ (C) is correct

$u = u_{x}^{2} + u_{y}^{2} \Rightarrow u_{B} > u_{A}$ (B) is correct

Hence (B), (C) and (D).

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Projectile motion

⏱ 2mℹ️ Source: QB

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