A street car moves rectilinearly from rest from station A to the next station B and stops. It's acceleration (f) is varying according to the law f = a − bx , where a and b are positive constants

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A street car moves rectilinearly from rest from station A to the next station B and stops. It's acceleration (f) is varying according to the law f = a − bx , where a and b are positive constants and x is the distance from station A . The distance between the two stations \& the maximum velocity are :-

TestHub · Accepted Answer

dx vdv ​ = a − bx ⇒ 2 v 2 ​ = ax − 2 bx 2 ​ Speed is zero again at x = b 2 a ​ also speed is max at x = b a ​ v max ​ = b ​ a ​

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