Physics - Kinematics Question with Solution | TestHub

velocity will be zero at ${\mathrm{t}}_2=1-\frac{1}{\sqrt{3}}$ second that ${\mathrm{t}}_2=1+\frac{1}{\sqrt{3}}\sec$

Acceleration changes its direction between ${\mathrm{t}}_1=0$ and ${\mathrm{t}}_2=2$

Acceleration remains constant in direction between ${\mathrm{t}}_1=0$ and ${\mathrm{t}}_2=2$

None of these