Start Free Mock LoginAlready registered? Login here

Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minQB

PhysicsMediuminteger

A missile rises vertically 1 km and then follows a parabolic path at $4 5^{\circ}$ elevation to strike an object at the same level 24 km away. Its velocity at the beginning of the parabolic path is: (Take $g = 10 m / s^{2}$ )

Answer:

1728

Solution:

$v^{2} = \frac{g x ^{2}}{x + h} = \frac{0.01 \times 576}{25} = 0.2304$
in
$k m^{2} / s^{2}, v = 0.48 km / s = 1728 km / h$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...