Paragraph for Questions 1 and 2: A particle starting from rest has a constant acceleration of 4 $m/s^{2}$ for 4 s. It then retards uniformly for the next 8 s and comes to rest.
Average speed of the particle during the motion $($ in $ms^{- 1})$ is

Question

Paragraph for Questions 1 and 2: A particle starting from rest has a constant acceleration of 4 $m/s^{2}$ for 4 s. It then retards uniformly for the next 8 s and comes to rest.

Average speed of the particle during the motion $($ in $ms^{- 1})$ is

TestHub · Accepted Answer

Maximum velocity: v ma x ​ = a t = 4 × 4 = 16 m/s Distance in first 4 s: s 1 ​ = 2 1 ​ × 4 × 16 = 32 m Distance in next 8 s (uniform retardation to rest): s 2 ​ = 2 1 ​ × 8 × 16 = 64 m Average speed = 12 32 + 64 ​ = 12 96 ​ = 8 m/s Answer: 8.00

Physics - Kinematics Question with Solution | TestHub

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