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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minQB

PhysicsMediuminteger

A particle moves with constant speed $3 m / s$ along the parabola $y = 2 x^{2}$ (SI units). Its acceleration at the point $x = 0$ is: (Answer in m/s².)

Answer:

Solution:

$a = 2 k v^{2} = 2 \times 2 \times 9 = 36 m / s^{2}$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

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