Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minPYQ_2007

PhysicsMediumsingle choice

A particle just clears a wall of height $b$ at distance $a$ and strikes the ground at a distance $c$ from the point of projection. The angle of projection is

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Answer:

Solution:

$a = (u cos α) t$ and $b = (u sin α) t - \frac{1}{2} g t^{2}$ $b = a tan α - \frac{1}{2} g \frac{a ^{2}}{u ^{2} c o s ^{2} α}$ also, $c = \frac{u ^{2} s i n 2 α}{g}$ $b = a tan α - \frac{a ^{2} g}{2} (\frac{s i n 2 α}{c g}) sec^{2} α$ $b = a tan α - \frac{a ^{2}}{2 c} 2 tan α$ $\Rightarrow (a - \frac{a ^{2}}{c}) tan α = b$ $tan α = \frac{b c}{a ( c - a )}$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2007

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