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PhysicsCalculusDifferentiationMedium2 minQB

PhysicsMediumnumerical

A tangent is drawn at point $P$ of curve $y = a x (x + b)$ . Find the value of $\frac{b}{a}$

Answer:

12.00

Solution:

$y = a x^{2} + ab x$

From the diagram, the curve passes through P = (2, 4).

$4 = 4 a + 2 ab$

The tangent slope at P is 1.

$\frac{d y}{d x}_{x = 2} = 4 a + ab = 1$

$ab = 3, a = - \frac{1}{2}$

$b = - 6, \frac{b}{a} = 12$

Subject:PhysicsTopic:CalculusSubtopic:Differentiation

⏱ 2mℹ️ Source: QB

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