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PhysicsCalculusBasic maths (Trigonometry, function, graph etc)Easy2 minQB

PhysicsEasyinteger

approximate value of $(1.002)^{100}$ is $n$ then $5 n$ is $____$ .

Answer:

Solution:

Using the approximation $(1 + x)^{n} \approx 1 + n x$ for small $x$ , we have $(1.002)^{100} \approx 1 + 100 (0.002) = 1.2$ .

Thus, $n = 1.2$ , and $5 n = 5 (1.2) = 6$ .

Stream:JEESubject:PhysicsTopic:CalculusSubtopic:Basic maths (Trigonometry, function, graph etc)

⏱ 2mℹ️ Source: QB

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