Start Free Mock LoginAlready registered? Login here

Physics - Calculus Question with Solution | TestHub

PhysicsCalculusDifferentiationMedium2 minQB

PhysicsMediuminteger

Find the rate of change of radius (in m/s) of a sphere when its radius is 4 cm and when its volume is changing at the rate of $\frac{4 π}{625} m^{3} / sec$ .

Answer:

Solution:

$V = \frac{4}{3} π R^{3} \Rightarrow \frac{d V}{d t} = 4 π R^{2} \frac{d R}{d t}$

$\frac{4 π}{625} = 4 π (\frac{4}{100})^{2} \frac{d R}{d t}$

$\frac{d R}{d t} = \frac{10000}{625 \times 16} = 1$ m/s.

Answer: 1

Subject:PhysicsTopic:CalculusSubtopic:Differentiation

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...