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PhysicsPractical physicsMiscellaneousEasy2 minQB
PhysicsEasynumerical

In a meter Bridge experiment resistancexis connected in the right gap. WhenR1andR2are connected in the left gap separately the balance points are40 cmand50 cmrespectively from the left end. Now if bothR1 & R2are connected in series in the left gap withxin the right gap then what will be the new balance point from the left end (incm)?

Answer:
62.50
Solution:

R1x= 4060 = 23....1, R2x= 5050 = 1 ..... 2

R1+R2x= l100–l.... (3) Add eq (1) & (2)

R1+R2x=23 + 1 = 53... (4) Placing eq (4) in (3)

5/3 =l100–l⇒ 500–5l = 3l

⇒ 8l=500∴l= 62.5 cm

Stream:JEESubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: QB

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