Figure shows a square current carrying coil of edge length L . The magnetic field on the coil is given by $B = \frac{B _{0} y}{L} \hat{i} + \frac{B _{0} x}{L} \hat{j}$ where $B_{0}$ is a positive constant.

Question

Figure shows a square current carrying coil of edge length L . The magnetic field on the coil is given by B = L B 0 ​ y ​ i ^ + L B 0 ​ x ​ j ^ ​ where B 0 ​ is a positive constant.

TestHub · Accepted Answer

F A B ​ = + B 0 ​ i l /2 k ^ F BC ​ = + B 0 ​ i l /2 k ^ F C D ​ = + B 0 ​ i l /2 k ^ F O A ​ = − B 0 ​ i l /2 k ^

Physics - Practical physics Question with Solution | TestHub

Options:(select one or more)

Doubts & Discussion