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PhysicsPractical physicsMiscellaneousMedium2 minPYQ_2020

PhysicsMediumsingle choice

A screw gauge has least count of $0.01 mm$ and there are $50$ divisions in its circular scale. The pitch of the screw gauge is:NEET 2020 (Phase 1)

Answer:

Solution:

The least count on screw gauge is given by, $L.C. = \frac{Pitch}{Number of division on circular scale}$

$\Rightarrow 0.01 mm = \frac{Pitch}{50}$

$\Rightarrow Pitch = 0.5 mm$

Stream:NEETSubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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