Physics - Practical physics Question with Solution | TestHub

$(\mathrm{R}=1.1\times 10^7{\mathrm{m}}^{-1},\mathrm{b}=1$ and $\sqrt{5/33}=0.39)$ Ans 7 (A) $\frac{1}{{\lambda }_{\alpha }}=\frac{3R}{4}(Z-1{)}^2$ $\Rightarrow (Z-1)=\sqrt{\frac{4}{3R{\lambda }_{\alpha }}}=\sqrt{\frac{4}{3\times 1.1\times 10^7\times 1.8\times 10^{-10}}}$ $=\frac{200}{3}\sqrt{\frac{5}{33}}=\frac{78}{3}=26.\square \square \mathrm{Z}=27$