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PhysicsPractical physicsMiscellaneousEasy2 minPYQ_2026

PhysicsEasysingle choice

In a vernier callipers, $20$ VSD coincide with $16$ MSD (each division of length $1$ mm). The least count of the vernier callipers is :NEET 2026 (Cancelled)

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Answer:

Solution:

Given $20$ VSD $= 16$ MSD.

$1$ VSD $= \frac{16}{20}$ MSD $= 0.8$ MSD.

Least count is given by $1$ MSD $- 1$ VSD.

Least count $= 1$ MSD $- 0.8$ MSD $= 0.2$ MSD.

Since $1$ MSD $= 1$ mm, we get Least count $= 0.2$ mm.

Converting to cm, Least count $= 0.02$ cm.

Answer: $0.02$ cm

Stream:NEETSubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2026

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