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Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousEasy2 minQB

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A vernier calliper has $20$ divisions on the vernier scale which coincide with $19$ divisions on the main scale. The least count of the instrument is $0.1 mm$ . The length of one main scale division is

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Solution:

$20$ division on vernier scale = $19$ division on the main scale

$20 (VRS) = 19 (MSR)$

$L.C = MSR - VSR = 0.1 mm$

$\Rightarrow MSR - \frac{19}{20} (MSR) = 0.1 mm$

$\Rightarrow MSR = 2 mm$

Stream:JEESubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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