Physics - Practical physics Question with Solution | TestHub

$\begin{array}{rl}& \text{ For a Metre bridge, }\\ & \frac{\mathrm{X}}{\mathrm{R}}=\frac{l_{\mathrm{X}}}{l_{\mathrm{R}}}\end{array}$ After doubling and interchanging the left and right gap resistances, the ratio of the resistances do not change. This means the null point does not change. $\therefore$ The new position will remain at $(100-l)$.