Diameter of a steel ball is measured using a Vernier calipers which has divisions of 0.1 cm on its main scale (MS) and 10 divisions of its Vernier scale (VS) match 9 divisions on the main scale. Three

Question

Diameter of a steel ball is measured using a Vernier calipers which has divisions of 0.1 cm on its main scale (MS) and 10 divisions of its Vernier scale (VS) match 9 divisions on the main scale. Three such measurements for a ball are given as:

S.No.	MS (cm)	VS divisions
1.	0.5	8
2.	0.5	4
3.	0.5	6

If the zero error is - 0.03 cm, then mean corrected diameter is:

TestHub · Accepted Answer

L.C. of Vernier calipers = 1 m a i n s c a l e d ivision T o t a l d i v i s o n s v e r n i e r s c a l e = 0.1 10 = 0.01 cm Reading of Vernier calipers = M . S . R . + L . C × v s d i v i s i o n s . d 1 = 0.5 + 0.01 × 8 d 2 = 0.5 + 0.01 × 4 d 3 = 0.5 + 0.01 × 6 ∴ Measured diameter are respectively 0 .58 cm 0 .54 cm , 0 .56 cm ∴ a v e r a g e d i a m e t e r = 0.58 + 0.54 + 0.56 3 = 1.68 3 = 0.56 Negative zero error is added in the average diameter to get the corrected diameter ∴ c o r r e c t e d d i a m e t e r = 0.56 - ( - 0.03 ) = 0.56 + 0.03 = 0.59 cm

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