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PhysicsErrorMiscellaneousHard2 minPYQ_2019

PhysicsHardsingle choice

A potentiometer wire $AB$ having length $L$ and resistance $12 r$ is joined to a cell $D$ of emf $ε$ and internal resistance $r$ . A cell $C$ having EMF $ε / 2$ and internal resistance $3 r$ is connected. The length $AJ$ , at which the galvanometer, as shown in the figure, shows no deflection is

Options:

Answer:

Solution:

Potential difference across $AJ = I R_{A J}$ ,

$= \frac{ε}{13 r} \cdot (\frac{12 r}{L} \cdot x)$

For no current in galvanometer,

$\frac{ε}{2} =$ potential difference across $AJ$

$\frac{ε}{2} = \frac{12 ε}{13 L} x$

$x = \frac{13L}{24}$

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2019

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