The diameter of a cylinder is measured using a vernier calipers with no zero error. It is found that the zero of the vernier scale lies between 5 . 10 cm and 5 . 15 cm of the main scale. The vernier s

Question

The diameter of a cylinder is measured using a vernier calipers with no zero error. It is found that the zero of the vernier scale lies between $5.10 cm$ and $5.15 cm$ of the main scale. The vernier scale has $50$ divisions equivalent to $2.45 cm$ . The $24^{th}$ division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is,

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Answer:

B

Solution:

$1 MSD = 0.05 $
$1 VSD = \frac{2.45}{50} = 0.04$
$Diameter of the cylinder$
$= MSR + L.C. \times 24$
$= 5.124 cm$

TestHub · Accepted Answer

1 MSD = 0.05 ​ 1 VSD = 2.45 5 0 = 0.04 Diameter of the cylinder = MSR + L.C. × 2 4 = 5.124 cm

Physics - Error Question with Solution | TestHub

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