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PhysicsNLMFBD & EquilibriumMedium2 minQB

PhysicsMediumsingle choice

Three blocks are arranged by the two string as shown in the diagram. Then the force exerted by the pullyon the clamp is

Answer:

Solution:

$\frac{3 g - 2 g}{10} = \frac{g}{10} m / s^{2} = a_{net}$

$T - 2 g = 2 \times g /10 T = 2 g + g /5 = \frac{11 g}{5} N = 22 N$

At pulley $B = 222$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: QB

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