Two blocks of m and 12 kg are placed side by side on a smooth horizontal surface as shown. Two horizontal forces $F_{1} = 18 N$ and $F_{2} = 36 N$ are applied. Then find the value of m (in kg) if m does not exerts any force on 12 kg.
$F_{1} = 18 N_{2} = 36 N$

Question

Two blocks of m and 12 kg are placed side by side on a smooth horizontal surface as shown. Two horizontal forces $F_{1} = 18 N$ and $F_{2} = 36 N$ are applied. Then find the value of m (in kg) if m does not exerts any force on 12 kg.

$F_{1} = 18 N_{2} = 36 N$

TestHub · Accepted Answer

No contact force means each block accelerates the same under its own force alone m F 1 ​ ​ = 12 F 2 ​ ​ , so m 18 ​ = 12 36 ​ m = 6 kg

Physics - NLM Question with Solution | TestHub

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