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PhysicsNLMFrictionMedium2 minQB

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For shown situation the acceleration of block is represented by. (Here t is time in second) $(g = 10 ms^{- 2})$

Answer:

Solution:

Block moves of $2 t \geq (0.4) (10) (10) \Rightarrow t \geq 20 s$ ; Just after start its acceleration $a = \frac{40 - 30}{10} = 1 ms^{- 2}$

After that $a = \frac{2 t - 30}{10} = \frac{t}{5} - 3 \Rightarrow$ Slope of a-t curve $tan^{- 1} (\frac{1}{5}) = tan^{- 1} (0.2)$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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