Physics - NLM Question with Solution | TestHub

Supports A ($2m$), so $F_{s1}=2mg$.

Supports E ($m$), so $F_{s2}=mg$.

String Tension ($T$)

$3mg$ (Left: $m_{B}g+F_{s1}=3mg$

Right: $m_{C}g+m_{D}g+F_{s2}=3mg$).

($F_{s1}\to 0$)

Block A: $a_A=\frac{2mg}{2m}=\mathbf{g}\downarrow$ (Option A)

($F_{s2}$ stays $mg$)

Block E: $a_E=0$ (Option C)

Driving force (Right): $(m_C+m_D)g+F_{s2}=2mg+mg=3mg$.

Opposing force (Left): $m_{B}g=mg$.

Net Force: $3mg-mg=2mg$.

Acceleration: $a=\frac{2mg}{3m}=\frac{2g}{3}\downarrow$ (Option B)

Summary

$a_A=g\downarrow$

$a_D=\frac{2g}{3}\downarrow$

$a_E=0$