A block is moving on an inclined plane making an angle 4 5 ∘ with the horizontal and the coefficient of friction is μ . The force required to just push it up the inclined plane is 3 times the force re

Question

A block is moving on an inclined plane making an angle 4 5 ∘ with the horizontal and the coefficient of friction is μ . The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define N = 10 μ , then N is

TestHub · Accepted Answer

​ F 1 ​ = m g sin θ + μ m g cos θ F 2 ​ = m g sin θ − μ m g cos θ ​ Given that, F 1 ​ = 3 F 2 ​ or ( sin 4 5 ∘ + μ cos 4 5 ∘ ) = 3 ( sin 4 5 ∘ − μ cos 4 5 ∘ ) On solving, we get μ = 0.5 ∴ N = 10 μ = 5 ∴ Answer is 5 . Analysis of Question Question is simple. Only one has to take care of direction and magnitude of friction.

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