Start Free Mock LoginAlready registered? Login here

Physics - NLM Question with Solution | TestHub

PhysicsNLMFBD & EquilibriumMedium2 minQB

PhysicsMediuminteger

In adjacent diagram, the ratio of mass $m_{1}$ and $m_{2} (m_{1} : m_{2})$ so that they remain at rest, given all surfaces are smooth and inclined faces are fixed is 16/X. Value of x is

Answer:

Solution:

For $m_{1}$ : $N_{1} cos 3 7^{\circ} = m_{1} g$ and $N_{1} sin 3 7^{\circ} = N$ .

For $m_{2}$ : $N_{2} cos 5 3^{\circ} = m_{2} g$ and $N_{2} sin 5 3^{\circ} = N$ .

$\frac{m _{1}}{m _{2}} = \frac{t a n 5 3 ^{\circ}}{t a n 3 7 ^{\circ}} = \frac{4/3}{3/4} = \frac{16}{9}$

$X = 9$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...