Physics - NLM Question with Solution | TestHub

$N=mg-F\sin 37^{\circ }=20-12=8$ N - (D) correct.

Limiting friction $=1.5\times 8=12$ N $<F\cos 37^{\circ }=16$ N, so the block slides with $a=\frac{16-12}{2}=2m/{\mathrm{s}}^2$ - (A) correct.

Work done by $F$ over 2 m is $16\times 2=32$ J - (B) correct; work done by friction is $-12\times 2=-24$ J - (C) correct.