A 2 kg block is kept at rest on a rough horizontal surface having coefficient of static and kinetic friction as μ s = 0.2 and μ k = 0.1 respectively. A Force F = 2 t starts acting on the object (w

Question

A 2 kg block is kept at rest on a rough horizontal surface having coefficient of static and kinetic friction as $μ_{s} =$ 0.2 and $μ_{k} = 0.1$ respectively. A Force $F = 2 t$ starts acting on the object (where ' t ' is in seconds). If the speed of block is V ( in m/s ) then find 2V at $t = 3 s . (g = 10 m / s^{2})$

TestHub · Accepted Answer

f s , ma x ​ = 0.2 ( 2 × 10 ) = 4 ⇒ 2 t = 4 ⇒ t = 2 s f k ​ = 0.1 ( 20 ) = 2 a = 2 2 t − 2 ​ = t − 1 v = ∫ 2 3 ​ ( t − 1 ) d t = 1.5 m / s

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Doubts & Discussion

JEE Main + Advanced (1 year 12th class)