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PhysicsNLMFrictionMedium2 minQB

PhysicsMediummultiple choice

System is shown at an instant. There is friction only between 2 kg and ground and rest all surfaces are smooth. Then

Answer:

B, D

Solution:

FBD of 5 kg

$\Rightarrow k x = 5 \times 2 = 10 N$

FBD of 4 kg

$\Rightarrow T + k x T + 10 T = 4 (3) = 12 = 2 N$

$\Rightarrow T e n s i o ni s n o n - zero$

$\Rightarrow 2 k g an d 4 k g m u s t m o v e w i t h s am e a cce l er a t i o n$

$\Rightarrow a cce l er a t i o n o f 2 k g = 3 m / s^{2}$

$\Rightarrow FB Do f 2 k g$

$\Rightarrow 10 - 2 - 20 μ 20 μ μ = 3 (2) = 2 = 0.1$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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