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Physics - NLM Question with Solution | TestHub

PhysicsNLMFBD & EquilibriumMedium2 minQB

PhysicsMediumsingle choice

A stiff horizontal spring of weight W and force constant k is suspended in a horizontal position by two light strings attached to its two ends. Each string makes an angle $θ$ with the vertical. The extension of the spring is :

Options:

Answer:

Solution:

Each string has tension $T$ at angle $θ$ with the vertical. Vertical equilibrium of the spring: $2 T cos θ = W$ .

Horizontal: the spring tension equals the horizontal pull $T sin θ = k x$ .

$\frac{k x}{W} = \frac{T sin θ}{2 T cos θ} = \frac{tan θ}{2} \Rightarrow x = \frac{W tan θ}{2 k}$ .

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: QB

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