Two blocks, 3 kg on top and 6 kg at the bottom, rest on a smooth horizontal floor; the coefficient of friction between the blocks is μ = 0.4 . A horizontal force F = 27 N is applied on the 3 kg block.

Question

Two blocks, 3 kg on top and 6 kg at the bottom, rest on a smooth horizontal floor; the coefficient of friction between the blocks is μ = 0.4 . A horizontal force F = 27 N is applied on the 3 kg block. The acceleration of the 6 kg block is: (Take g = 10 m/s²)

TestHub · Accepted Answer

Maximum friction = 0.4 × 3 × 10 = 12 N . Moving together would need a = 3 m/ s 2 and friction 18 N > 12 N, so the blocks slip; the 6 kg block is driven by kinetic friction a = 6 12 ​ = 2 m/ s 2 . Option A.

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