Physics - NLM Question with Solution | TestHub

The table pushes the block upward with 10 N. By Newton's third law, the block pushes the table downward with 10 N. Thus A is correct; B and C are false.

$m=\frac{9.8}{9.8}=1\mathrm{kg}$

$F_{\text{net }}=10-9.8=0.2\mathrm{N}$ upward.

$a=\frac{F_{\text{net }}}{m}=\frac{0.2}{1}=0.2\mathrm{m}{\mathrm{s}}^{-2}$ upward.

Hence D is correct. Weight and normal force act on the same block, so they are not an action-reaction pair.