Physics - NLM Question with Solution | TestHub

Block loose contact $\Rightarrow 10t=100$

$F_{net}=10t-100=10\times a$

$a=t-10$

$$\frac{dv}{dt}=t-10$$

$${\int }_0^{v}dv={\int }_{10}^t(t-10)dt$$

$$v(t)={\left[\frac{t^2}{2}-10t\right]}_{10}^t=\frac{t^2}{2}-10t-[50-100]$$

$$v(t)=\frac{t^2}{2}-10t+50$$

At $t=20sec$, $v=200-200+50=50m/s$

$$\frac{dx}{dt}=\frac{t^2}{2}-10t+50$$

$$\int dx={\int }_{10}^{20}\left[\frac{t^2}{2}-10t+50\right]dt$$

$$x=\frac{500}{3}m$$