List-I contains values of F and List-II contains the corresponding values of acceleration. (Take: $g = 10 m / s^{2}$ )
List-I
List-II
(I) $F = 20 N$
(P) $5.4 m / s^{2}$
(II) $F = 100 N$
(Q) $0 m / s^{2}$
(III) $F = 40 N$
(R) $3.2 m / s^{2}$
(IV) $F = 10 N$
(S) $7.7 m / s^{2}$

(T) $2.5 m / s^{2}$

Question

List-I contains values of F and List-II contains the corresponding values of acceleration. (Take: $g = 10 m / s^{2}$ )

List-I	List-II
(I) $F = 20 N$	(P) $5.4 m / s^{2}$
(II) $F = 100 N$	(Q) $0 m / s^{2}$
(III) $F = 40 N$	(R) $3.2 m / s^{2}$
(IV) $F = 10 N$	(S) $7.7 m / s^{2}$
	(T) $2.5 m / s^{2}$

TestHub · Accepted Answer

Normal force N = F cos 3 7 ∘ = 0.8 F ; f s , ma x ​ = 0.4 F , f k ​ = 0.32 F ; vertical drive = m g − F sin 3 7 ∘ = 40 − 0.6 F F = 20: slides, a = 4 28 − 6.4 ​ = 5.4 ( P ) F = 100: drive 20 < f s , ma x ​ = 40 , rest, a = 0 (Q). F = 40: drive 16 = f s , ma x ​ , a = 0 (Q). F = 10: slides, a = 4 34 − 3.2 ​ = 7.7 ( S ) . Option C.

Physics - NLM Question with Solution | TestHub

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