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Physics - NLM Question with Solution | TestHub

PhysicsNLMChallenging application of NLMMedium2 minQB

PhysicsMediumsingle choice

Two blocks $m_{1}$ and $m_{2}$ are connected with a compressed spring and placed on a smooth horizontal surface as shown in figure. Force constant of spring is k . Under the influence of forces $F_{1}$ and $F_{2}$ . At an instant blocks move with common acceleration $a_{0}$ . At that instant force $F_{2}$ is suddenly withdrawn. Mark correct option.

Options:

Answer:

Solution:

Spring force does not change instantaneously.

Thus for $m_{1}; a_{1} = a_{0}$

$F_{S_{p}} = m_{2} a_{2}$

for $m_{2}$

$F_{S_{p}} - F_{2} = m_{2} a_{0}$

Initially

$F_{S_{p}} = F_{2} + m_{2} a_{0}$

from (i) and (ii) $a_{2} = \frac{F _{2}}{m _{2}} + a_{0}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Challenging application of NLM

⏱ 2mℹ️ Source: QB

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