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PhysicsNLMFrictionHard2 minPYQ_2024
PhysicsHardsingle choice

A block of mass 5 kg is placed on a rough inclined surface as shown in the figure. If F1 is the force required to just move the block up the inclined plane and F2 is the force required to just prevent the block from sliding down, then the value of F1F2 is: [Use g=10 m s-2]

Question diagram: A block of mass 5 kg is placed on a rough inclined surface a

Options:

Answer:
B
Solution:

Limiting friction force is, fmax=μmg cosθ

=0.1×50×32

=2.53 N

For first case:

We can write, F1=mg sinθ+fmax

=25+2.53

For second case:

F2=mg sinθfmax

=252.53

F1F2=53 N

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction
2mℹ️ Source: PYQ_2024

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