A man of mass 60 kg is standing on a light weighing machine kept in a lift. Lift starts from rest and moves up with a velocity v = t 2 + 2 t where t is time in second. At t = t 0 machine shows a wei

Question

A man of mass 60 kg is standing on a light weighing machine kept in a lift. Lift starts from rest and moves up with a velocity $v = t^{2} + 2 t$ where t is time in second. At $t = t_{0}$ machine shows a weight which is double the actual weight of man. Find $t_{0}$ (in second). $(g = 10 m / s^{2})$

Answer:

4

Solution:

$a = \frac{d v}{d t} = 2 t + 2$

Reading doubles: N = 2mg, so a = g = 10

$2 t_{0} + 2 = 10$ , so $t_{0} = 4 s$

Answer 4

TestHub · Accepted Answer

a = d t d v ​ = 2 t + 2 Reading doubles: N = 2mg, so a = g = 10 2 t 0 ​ + 2 = 10 , so t 0 ​ = 4 s Answer 4

Physics - NLM Question with Solution | TestHub

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