The coefficient of friction between the two blocks shown in the figure is μ = 0.4 and between the lower block and the ground is zero. The blocks are given velocities of 2 m s - 1 and 8 m s - 1 respect

Question

The coefficient of friction between the two blocks shown in the figure is $μ = 0.4$ and between the lower block and the ground is zero. The blocks are given velocities of $2 m s^{- 1}$ and $8 m s^{- 1}$ respectively in the direction shown in the figure. In how much time (in seconds) the slipping between the blocks will stop?

TestHub · Accepted Answer

The common velocity of the blocks can be calculated as follows 3 v = 1 × 2 + 2 × 8 v = 6 m s - 1 The acceleration of the 1 kg block is a = μ g = 4 m s - 2 v = 2 + 4 t ⇒ t = 1 s

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